Question

ength of one of the equal sides of an isosceles triangle is 4 cm. If its base is 2 cm then what is its area? a. √15cm2 b. √13cm2 c. √12cm2 d. √14cm2 *

Answer 1

Answer:

a. √15 cm2

Step-by-step explanation:

height of the triangle= √(4²-1²)=√15

area=1/2 ×2×√15=√15 cm²

Answer 2

${\tt{\underline{Given :-}}}$

The Length of one of the equal sides of an isosceles triangle is 4 cm. If its base is 2 cm then

${\tt{\underline{Need\;to \;Find:-}}}$

what is its area? a. √15cm2 b. √13cm2 c. √12cm2 d. √14cm2 *

${\tt{\underline{Answer :-}}}$

Here, first of all, we need to find the perimeter of the triangle

The Perimeter of triangle = Sum of all sides

=> Perimeter = 4 + 4 + 2

=> Perimeter = 10 cm

Area by using heron's formulae

=> Semiperimeter = 1/2 × (Perimeter)

=> Semiperimeter = 1/2 × 10

=> Semiperimeter = 5 cm

=> Area = √s(s-a)(s-b)(s-c)

=> Area = √5(5-4)(5-4)(5-2)

=> Area = √5 × 1 × 1 × 3

=> Area = 1√(5 × 3)

=> Area = √15 cm²

Thus,

Option no. A (√15cm²) is correct

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