Math, asked by mahasri75, 9 months ago

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Evaluate sec41°• sin49°+cos49°• cosec41°+2/√3 tan20°•tan60°•tan70°-3(cos45°-sin90°)​
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Answers

Answered by Ritesh271
0

Answer:

7 - (3 / root2)

Step-by-step explanation:

Solution :-

= sec41°.sin49° + cos49°.cosec41° + 2/root3 tan20°.tan60°.tan70°-3(cos45°-sin90°)

= sec(90°-41°).sin49° + cos(90°-49).cosec41° + 2/root3

tan(90°-20°). root 3 . tan70°-3( 1 / root2 - 1 )

= cosec49°.sin49° + sin41°.cosec41° + 2cot70°.tan70°-3( 1-root2 / root2 )

= 1/sin49°.sin49° + sin41°.1/sin41° + 2/tan70°.tan70° -

( 3 - 3 root2 ) / root 2

= 1 + 1 + 2 - ( 3 - 3 root2 ) / root2

= ( 4 root2 - 3 + 3 root2) / root2

= ( 7 root2 - 3 ) / root2

= 7 - (3 / root2)

Answered by Anonymous
0

Answer:

Sorry I don't know the answer . I feel very sad for it. sorry

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