Chemistry, asked by raotd, 9 months ago

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Answered by Anonymous
1

Answer:

\begin{gathered}\begin{gathered}\\\\\sf \large \red{\underline{Question:-}}\\\\\end{gathered}\end{gathered}</p><p>

5. The measures of two adjacent angles of a parallelogram are in the ratio 3:2. Find the measure of each of the angles of the parallelogram.

\begin{gathered}\begin{gathered}\\\\\sf \large \red{\underline{Given:-}}\\\\\end{gathered}\end{gathered}</p><p>

The measures of two adjacent angles of a parallelogram are in the ratio 3:2.

\begin{gathered}\begin{gathered}\\\\\sf \large \red{\underline{To \: Find:-}}\\\\\end{gathered}\end{gathered}</p><p>

Find the measure of each of the angles of the parallelogram.

\begin{gathered}\begin{gathered}\\\\\sf \large \red{\underline{Solution :- }}\\\\\end{gathered}\end{gathered}</p><p>

\text{ \sf suppose the angles be equal to 3x and 2x}

\boxed{ \sf \orange{ we \: have \: ardjacent \: angles \: of \: a \: parallelogram \: = 180}}

\begin{gathered}\begin{gathered}\\ \sf \underline{ \green{putting \: all \: values : }}\end{gathered}\end{gathered}

\begin{gathered}\begin{gathered}\: \\ \sf \to \: 3x + 2 x = 180\: \\ \\ \sf \to \: \: \: \: \: \ : \: \: \: \: \:5x = 180 \\ \\ \: \sf \to \: \: \: \: \: \: \: \: \: \: \:x \: = \frac{180}{5} \\ \\ \sf \to \: \: \: \: \: \: \: \: \: \: \:x \: = \cancel{ \frac{180} {5} } \\ \\ \sf \to \: \: \: \: \: \: \: \: \: \: \purple{x = 36}\\\\\end{gathered}\end {gathered}</p><p></p><p></p><p>

</p><p>  \begin{gathered}\begin{gathered}\sf \to \: 3x \\ \sf \to \: 3 \times 36 \\ \sf \to \red{108 }\\ \\ \\ \sf \to \: 2x \\ \sf \to \: 2 \times 36 \\ \sf \to \orange{72} \\\end{gathered}\end{gathered}

Answered by Anonymous
17

Multiply the numerator and denominator with the same number, we can get the fractions equivalent of 6/11 (the simplest fraction) Therefore,the equivalent fractions of 6/11 are:-

12/22,18/33,24/44,30/55 & 36/66


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