Enme se kewal thin sankhyao ko jodne pr kaise 60 prapt ho 2.6.10.14.18.22.26.30.34.38.42.46.50.54.50.
Answers
Given : 2,6,10,14,18,22,26,30,34,38,42,46,50,54,58
To find : 3 numbers such that sum = 60
Solution:
26 + 34 = 60 ( 2 , 6 & 34 number used)
2,6,10,14,18,22,26,30,34,38,42,46,50,54,58
This is an AP
with d = 4 a = 2
aₙ = a + (n-1)d
=> aₙ = 2 + ( n - 1)4
=> an = 2 + 4n - 4
=> aₙ = 4n - 2
Any term will be of form 4n - 2
if we add any three terms
then sum would be 4a - 2 + 4b - 2 + 4c - 2
= 4(a + b + c) - 4 - 2
= 4(a + b + c - 1) - 2
= 4k - 2
Sum = 4 k - 2
60 = 4 * 15
= 4k - 2 can not be equal to 4 * 15
Hence sum can not be equal to 60
Hence its not possible to add 3 numbers to get 60
but if we do not use simple maths
then we can use three numbers
2 , 6 & 34
26 + 34
= 60
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