Question

Ensity of dry air containing only n2 and o2 is 1.146 gm/lit at 740 mm and 300 k. what is % composition of n2 by weight in the air. (a) 78% (b) 82% (c) 73.47% (d) 72.42%

Answer 1

Explanation:

We know that PV=nRT

Since, 1 atm= 760 mm of Hg

∴ 740 mm of Hg = 0.97 atm

M=

P

dRT

=

0.97

1.15×0.082×300

=29.16 g mol

−1

Let M

1

be mass fraction of N

2

M

2

be that of O

2

M

2

=(1−M

1

)

M

1

×28+M

2

×32=29.16

On solving 4W

1

=2.83

W

1

=0.7008

So percentage of Nitrogen is 70.08%

Answer 2

Answer:

d VB ji o ihu for tidy 7 fi yssredjmnc ui NB gf udyog ti di dm chi