Question

ent
103. Block A of mass m rests on the plank B of mass
3m which is free to slide on a frictionless horizo-
ntal surface. The coefficient of friction between
the block and plank is 0.2. If a horizontal force
of magnitude 2 mg is applied to the plank B,
the acceleration of A relative to the plank and
relative to the ground respectively, are:
A
2mg
is
10
lack
t of
lack​

Answer 1

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Answer 2

Answer:

10 m/s^2 and 6 m/s^2.

Explanation:

Since, from the question we get that the coefficient of friction between the two blocks are given as 0.2. So, the acceleration of the block A relative to the plank B will be acceleration a=μg(since F=ma or μN=ma or μmg=ma), or a=0.2g or 20m/s^2 if g is taken as 10 m/s^2.

Again, for the acceleration  of the block B relative to the ground will be acceleration a=F-μmg/mB or 2mg-0.2mg/3m which on solving we will get the value of acceleration as a=2-0.2/3g which will be 3/5g or 6m/s^2.