Question

Enter a number in each box to write the factored form of y2+11y+28

Answer 1

hey mate here is ur answer

y²+11y+28

=y²+7y+4y+28

=y(y+7)+4(y+7)

=(y+4)(y+7)

hope it helps.

Answer 2

We have to write the given expression in factored form by using the sum and product method.

Factorisation

$y^{2} +11y +28$

Here we have to find the 2 numbers that satisfy the below conditions.

Coefficient of y = sum = 11

Constant term = Product = 28

The 2 numbers satisfying above 2 conditions are 7 and 4.

$7+ 4 = 11\\7*4=28$

Thus the expression can be given as,

$y^{2} + 4y +7y+28$

Taking common terms as,

$y(y+4)+7(y+4) \\=(y+4)(y+7)$

So the given expression is factorised as, $(y+4)(y+7)$