Question

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. A car accelerates uniformly from 18 Km/h to 54 km/h in 5 seconds. Calculate
() the acceleration and
(ii) the distance covered by the car in the given time. 15
(5 Points)
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4. Give two differences between compound and a mixture.​

Answer 1

Given:-

• Initial velocity of car (u) = 18km/h = 18×5/18= 5m/s

• Final velocity of the car (v) = 54km/h =54×5/18= 15m/s.

• Time Taken by car (t) = 5s .

To Find:-

• Acceleration and Distance covered by car.

Solution:-

(i) Acceleration

By using 1st equation of motion

⟹ v = u+at

Put the value which is given above

⟹ 15= 5 + a×5

⟹ 15-5 = a×5

⟹ 10 = a×5

⟹ a =10/5

⟹ a = 2m/s²

∴ The acceleration of the car 2m/s².

And ,

(ii) Distance

By using 2nd equation of motion

⟹s = ut +1/2at²

Put the value which is given above

⟹ s = 5×5 + 1/2×2×5²

⟹ s = 25 + 25

⟹ s = 50m

∴ Distance covered by car is 50m.

(4) Difference between Compound and Mixture are :-

⚈Compound⚈

• The element combines or react to form compounds.

• The compound content two or more element in a fixed ratio by mass.Itscomposition is always fixed.

• A compound is always homogeneous.

• The properties of compound are entirely different from those of its constituents.

⚈Mixture⚈

• In a mixture the element or compound just mix together.

• The components of a mixture may be present in any ratio. Its composition is variable.

• A mixture may be homogeneous for heterogeneous.

• A mixture shows the properties of its constituents.