Question

Enthalpy change for the raction,
4H(g) → 2H2(g) is - 869.5 kJ
The dissociation energy of H-H bond is:
(a) + 217.4 kJ (b)-434.8 kJ
(c)-869.6 kJ (d) + 434.8 kJ​

Answer 1

Answer:

434.8kj

Explanation:

Given reaction:     2 4 H g 2 H g  H = B.D.E. of reactants – B.D.E. of products = 0 – 2 × HH–H = – 2HH–H This is equal to – 869.6 kJ  – 2HH–H = – 869.6 kJ  HH–H = + 434.8 kJ