Question

Enthalpy of solution of BaCl, and BaCl, 2H,0 are
-x and y kJ/mol respectively. The enthalpy of
hydration of BaCl2 to BaCl2.2H20 is​

Answer 1

Answer:

(4)

Explanation:

Dear Student,

Enthalpy of hydration= Enthalpy of solution of BaCl2−enthalpy of solution of BaCl2.2H2O                                     =−x−y                                     =−(x+y) kJ/molHence, correct ansnwer is (4)