Question

Entropy of black body radiation is given by, $S = \frac{4}{3}$σ$V^{1/4}U^{3/4}$, when U is internal energy, V is the volume and σ is the stephans constant. What is the temperature of the radiation.

Answer 1

Answer:

refer to attachment..Entropy of black body radiation is given by, $S = \frac{4}{3}$σ$V^{1/4}U^{3/4}$, when U is internal energy, V is the volume and σ is the stephans constant. What is the temperature of the radiation.