Question

Entropy of vaporisation of water at 100°C, if molar
heat of vaporisation is 9710 cal mol-1 will be
(1) 20 cal mol-1 K-1. (2) 26.0 cal mol K-1
(3) 24 cal mol-1 K-1 (4) 28.0 cal mol-1 K-1​

Answer 1

Answer:

Vaporization of liquid leads to an increase in the degree of disorder or entropy. Entropy of vaporization is a measure of change in entropy during the process of vaporization. This entropy is positive. Entropy of vaporization ca be calculated by the following formula.

ΔS_{vap} =\frac{H_{vap} }{T}

Molar heat of vaporization of water is 9710 cal/mol

Boiling point of water is 100 ^{0}C =373K

Therefore Entropy of vaporization = \frac{9710 cal/mol}{373K}

=26.03 cal/mol/K

Thanks for the question