Question

Epand the following

1 (m+n) = m + __ + __​

Answer 1

Answer:

Step-by-step explanation:

1(m+n)=

m+n+0

Answer 2

Answer:

1+x) m (1−x) n =(1+mx+

2!m(m−1)x 2)(1−nx+ 2!n(n−1) x2 )=1+(m−n)x+[ 2n −mn+ 2(m 2 −m) ]x 2

Given m−n=3 or n=m−3

Hence

2n 2−n −mn+ 2m 2 −m =6

= 2(m−3)(m−4) −m(m−3)+ 2m 2−m

=−6⇒m 2 −7m+12−2m 2+6m+m 2 −m+12=0

⇒−2m+24=0⇒m=12.