Question

Epinephrine (adrenaline) is a hormone secreted into the bloodstream in times of stress. It contains 59.0% C, 7.15% H, 26.20% O, and 7.65% N and has a molar mass of 183 g/mol. What is its molecular formula?

Answer 1

Here is the answer:-C9H13NO3

Answer 2

The molecular formula of Epinephrine is $C_9H_{13}NO_3$.

To calculate the molecular formula of given compound the following steps must be followed:

Step 1: Find the moles of each constituents present in the compound.

Step 2: Divide each mole value with the smallest mole value obtained.

Step 3: Write the empirical formula

Step 4: Calculate the molar mass of empirical formula.

Step 5: Divide the given molar mass with the Empirical formula molar mass.

Step 6: Multiply each subscript of the empirical formula with the obtained answer.

Step 7: Molecular formula is obtained.

Base on the given data it is inferred that:

Carbon = 59.0g

Hydrogen = 7.15g

Oxygen = 26.20g

Nitrogen = 7.65g

Step 1:

Number of moles of Carbon = $\frac{Given mass}{Molar mass} = \frac{59.0}{12.0107}= 4.9122$

Number of moles of hydrogen = $\frac{7.15}{1.00794} = 7.0936$

Number of moles of Oxygen = $\frac{26.20}{15.994}= 1.6381$

Number of moles of nitrogen = $\frac{7.65}{14.0067} = 0.5461$

Step 2:

Smallest mole value obtained is 0.5461

∴

C = $\frac{4.9122}{0.5461}= 8.99$ = 9

H = $\frac{7.0936}{0.5461}= 12.98$ = 13

O = $\frac{1.6381}{0.5461}= 2.99$ = 3

Step 3:

The Empirical formula for the given compound is $C_9H_{13}O_3N$

Step 4:

Molar mass for empirical formula is :

9(12)+13(1)+3(16)+1(14) = 108+13+48+14=183g.

Step 5:

$\frac{Molar mass}{Empirical formula mass} = \frac{183}{183} = 1$

Step 6:

$C_{9\times1} = C_9$

$H_{13\times1}=H_{13}$

$O_{3\times 1}=O_3$

N = 1

Step 7:

The molecular formula of the Epinephrine is $C_9H_{13}O_3N$ or $C_9H_{13}NO_3$.

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