Math, asked by anusinghanurag564, 1 year ago

Epoy and junjun can do a certain job in 10 hours if they work together. If Epoy can do the job in 15 hours, how long will it take junjun to do the job alone?

Answers

Answered by amitnrw
5

Answer:

Junjun will take 30 hrs to do job alone

Step-by-step explanation:

Epoy can do the job in 15 hours

=> Epoy 1 hr Work = 1/15

Let say junjun can do the job in J hours

=> Junjun 1 hr job = 1/J

Epoy and junjun can do a certain job in 10 hours

=>Epoy and junjun together 1 hr job = 1/10

1/15 + 1/J = 1/10

=> 1/J = 1/10 - 1/15

=> 1/J = (3 - 2)/30

=> 1/J = 1/30

=> J = 30

Junjun will take 30 hrs to do job alone

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