eq.(x^2+1)^2-x^2=0 has how many real roots
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Answer:
It will have 4 roots. After simplification.
Step-by-step explanation:
(x^2)^2+2(x^2)(1)+(1)^2-x^2
I.e. x^4+2x^2+1-x^2
x^4+x^2+1
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