Eqn of a circle has radius 3 and its center lies on y=x-1
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equation of circle
if r=3,
centre lies at y=x-1
let centre of the circle (a,b)
b=a-1
centre(a,a-1)
equation of circle
x^2+y^2=r^2
(x-a)^2 + (y-a+1)^2=9
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