Question

eqn1:x-y=3 eqn2:x/3+y/2=6 by substitution method pls answer immediately ​

Answer 1

Answer:

x=3-y ----(i)

putting x in eq -- (ii)

(3-y)/3+y/2=6

(6-2y +3y)/6=6

6-y=36

y= - 30 ans

Step-by-step explanation:

Hope it is helpful for you

Answer 2

$x-y=3 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: .....(1) \\ \frac{x}{3} + \frac{y}{2} = 6 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: .....(2) \\ we \: pick \: either \: of \: the \: equations \: and \: write\\</p><p> \: one \: variable \: in \: terms \: of \: other.\\</p><p>let \: us \: consider \: the \: equation \: (1) \\ x - y = 3 \\ x = y + 3 \\ substitute \: the \: value \: of \: x \: \: in \: equation \: (2) \\ \frac{y + 3}{3} + \frac{y}{2} = 6 \\ \frac{2y + 6 + 3y}{6} = 6 \\ 5y + 6 = 36 \\ 5y = 36 - 6 \\ 5y = 30 \\ y = \frac{30}{5} \\ y = 6 \\ substitute \: the \: value \: of \: y \: \: in \: equation \: (1) \\ x - 6 = 3 \\ x = 3 + 6 \\ x = 9$