Question

equal 13, B equal 14, c equal 15 find the area of triangle

Answer 1

Hey Mate,

Given,

a = 13, b = 14, c = 15

Since, All the lengths of the sides are given, we will use Heron's Formula to calculate the area of the triangle.

Heron's Formula :-

Area of a Triangle =  \sqrt{s(s-a)(s-b)(s-c)}                                                             ( Where s = Perimeter of Triangle ÷ 2 )

On substituting the values of a as 13. b as 14 and c as 15 in the given formula, we get:-

=> Area of the Triangle = $\sqrt{(21)*(21 - 13)*(21 - 14)*(21 - 15)}$

=> Area of the Triangle = $\sqrt{(21)*(8)*(7)*(6)}$

=> Area of the Triangle = $\sqrt{7056}$

=> Area of the Triangle = 84

Therefore, the area of the triangle is 84, when a = 13, b = 14 and c = 15.

Hope it Helps!

Answer 2

Answer:

13 , 14 and 15 are the lengths of sides of Triangle ABC

Ar(ABC) = √S(S - 13)(S - 14)(S - 15)

S = perimeter / 2 = (13+14+15) / 2=21

Ar(ABC) = √21 x 8 x 7 x 6 = √8064 = 89.79 unit²