Question

equal arcs of a circle substained equal angles at the center​ .prove this with diagram​

Answer 1

a circle with centre 'O'

let A and B are the chords of the circle

ie,AB=CD

to proove : <AOB=<DOC

proof:

in∆AOB&∆DOC

AO=OD. (radius)

AB=CD. (chords)

OB=OC. (radius)

ie,∆AOB=~∆DOC. ( from sss rule)

ie,<AOB=<DOC. (CPCT theorm )

hence proved

Answer 2

Answer:

Congruent arcs (or equal arcs) of a circle subtend equal angles at the centre. In the figure, Arc AB = Arc CD & thus, it is observed that ∠1 =∠2.. Theorem 8: The angle subtended by an arc at the centre is double the angle subtended by it at any point on the remaining part of the circle.

Step-by-step explanation:

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