equal chord of a circle is equal diastance from the circle
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Equal chords of a circle are equidistant from its center. Proof: Compare ΔOAX Δ O A X with ΔOCY Δ O C Y . By the RHS criterion, ΔOAX≡ΔOCY Δ O A X ≡ Δ O C Y . Thus, OX = OY, which means that AB and CD are equidistant from O.
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