Equal chord of a circle subtend equal angle at the centre
Answers
Answered by
0
Answer:
Let us consider two chords of a circle with centre O as shown the two chords beAB and CD
As given in this question two chords are equal so
AB=CD
To prove:∠AOB=∠DOC
Now let us consider the△AOB and △DOC
AO=OD (radius of the circle )
AB=CD ( given )
$$ OB = OC (radius of circle )
∴ΔAOB≅ΔDOC (SSS congruency rule )
∴∠AOB=∠DOC
Hence, poved
Answered by
0
Answer:
Here is the answer
Step-by-step explanation:
Hope it helped u
Attachments:
Similar questions