Question

equal chords AB and CD of a circle with centre o intersect each other at right Angled at E. If M and N are the midpoint of AB and CD respectively. prove that angle OEM = angle OEN =45 DEGREE. what type of quadrilateral is OMEN.

Answer 1

We know that mid point of chord joining the center is perpendicular to chord so 
angle ONE = angle OME = 90 degree
Also angle MEN = 90 degree
So ONEM is a square of rectangle. Again equal chord are equidistance from the center so OM = ON And hence ONEM is a square. Now we know that diagonal of a square bisect the angle so 
angle OEN=angle OEM=90/2=45 degree


Hope this would clear your doubt about the topic.
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Answer 2

Answer:

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