equal chords of a circle subtend equal angles at the centre
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Step-by-step explanation:
let AB andCD be the chords of a circle with centre 0
where angle AOB is equal to angle COD
To prove:AB equal toCD
Proof: in triangle AOB and triangleCOD,we have
OA equal to OC (radii of a circle)
angle AOB equal to angleCOD
OB equal to OD(radii of a circle)
therefore triangle AOB congruent to triangleCOD(by SAS rule)
therefore AB equal toCD (by cpct)
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