Question

Equal forces Fact on isolated bodies A and B. The mass of A is 3/5 times that of B. The magnitude of the acceleration of B is times that of A.​

Answer 1

Answer:

The magnitude of acceleration of A is also 3/5 times that of B.

Explanation:

Let us consider the scenario with the help of the force formula. We know that,

                  F = ma

where, F = force,

           m = mass

           a = acceleration

From this formula we can conclude that force is directly proportional to both mass and acceleration.

Given that the forces acting on both the isolated bodies A and B. So, let us assume the mass of body B be 'x'. Then the mass of body A will be 3/5x. Let the acceleration of the body B be y' and that of A be y.

Since the force of both the bodies are equal, we may equate them.

Putting the given value in the formula, we get:

                   F = ma

                  xy' = 3/5x y

                    y' = 3/5y

Hence, we can conclude that magnitude of acceleration of A is 3/5 times that of B.

Answer 2

Given : Equal forces  act on isolated bodies A and B.

The mass of A is 3/5 times that of B.

To Find :  The magnitude of the acceleration of B is times that of A.​

Solution:

Assume

Force = 15x   N

Mass of B =  5y kg

Mass of A = (3/5)5y  = 3y  kg

Force = Mass * acceleration

F = ma

a = F/m

acceleration of A  = 15x/3y  = 5(x/y)   m/s²

acceleration of B  = 15x/5y  = 3(x/y)   m/s²

acceleration of B /  acceleration of A   =  3(x/y)  /  5(x/y)

=> acceleration of B /  acceleration of A   =  3/5

=> acceleration of B = (3/5)  acceleration of A  

=> The magnitude of the acceleration of B is (3/5)  times that of A.​

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