Equal heat is given to two objects A
and B of mass 1 g. Temperature of A
increases by 3 °C and B by 5 °C.
Which object has more specific heat?
And by what factor?
5
Answers
Answer:
Explanation:
Given that mass of A and B is equal and =1g=m
A
=m
B
Given change in temperature of A=ΔT
A
=3
0
C
change in term. of B=ΔT
B
=5
0
C
Given that Equal amount of heat is applied to both
for A:Q=m
A
S
A
ΔT
A
=3S
A
............(i)
for B:Q=m
B
S
B
ΔT
B
=5S
B
............(ii)
Where S
A
and S
B
are specific heat of A and B
From eq (i),(ii)
3S
A
=5S
B
⇒
S
A
=
3
5
S
B
Hence specific heat of A is greater than that of B by a factor of 5/3
Answer:
Given that mass of A and B is equal and =1g=m
A
=m
B
Given change in temperature of A=ΔT
A
=3
0
C
change in term. of B=ΔT
B
=5
0
C
Given that Equal amount of heat is applied to both
for A:Q=m
A
S
A
ΔT
A
=3S
A
............(i)
for B:Q=m
B
S
B
ΔT
B
=5S
B
............(ii)
Where S
A
and S
B
are specific heat of A and B
From eq (i),(ii)
3S
A
=5S
B
⇒
S
A
=
3
5
S
B
Hence specific heat of A is greater than that of B by a factor of 5/3