equal heat is given to two objects a and b of mass 1kg temperature of a is increase hg 50c which object has more specific heat and by what factor
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SA=5/3 SB
Given that mass of A and B is equal and = 1g = mA = mB
Given change in temperature of A = ΔTA = 3°C
change in tem. of B = ΔTB = 5°C
Given that Equal amount of heat is applied to both
for A : Q = mAsAtA = 3SA (i)
for B : Q = mBsBtB = 5SB (ii)
When SA and SB are specific heat of A and B
From eq (i),(ii)
3 SA = 5 SB
SA = 5/3 SA
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