equal heat is givqn to two object A and B of mass 1 g. temperatuer of A increases by 3 °c. and B by 5° c. whitch object has more specific heat? and by what factor?
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Hey.
Here is the answer.
As, Q = m c ∆T
and as equal heat is given so for both the objects Q is same
∆T for A , ∆Ta = 3℃ & ∆T for B, ∆Tb = 5℃
so, for A , Q = 1g × c × 3℃ = 3c J
So, c of A = Q/3
and, for B, Q= 1g× c × 5℃ = 5c J
So, c of B = Q/5
Hence, c of A is more.
Also, Q/3 / Q/5 = 5/3
So, c of A is more by factor of 5/3 than B.
Thanks.
Here is the answer.
As, Q = m c ∆T
and as equal heat is given so for both the objects Q is same
∆T for A , ∆Ta = 3℃ & ∆T for B, ∆Tb = 5℃
so, for A , Q = 1g × c × 3℃ = 3c J
So, c of A = Q/3
and, for B, Q= 1g× c × 5℃ = 5c J
So, c of B = Q/5
Hence, c of A is more.
Also, Q/3 / Q/5 = 5/3
So, c of A is more by factor of 5/3 than B.
Thanks.
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