Question

Equal length of magnesium ribbon is taken in 2 test tube A &B H2so4 is added to test tube A and h2co3 is added to test tube B in equal amount
(1)Identify the test tube showing vigorous reactions .
(2) name the gas elaborated in both test tube . How will you prove it Elaboration
(3) write the chemical reaction of both reaction.

Answer 1

1.testube A show vigorous reaction
2.hydrogen gas elaborate in both reaction.
3.
mg+H2SO4------->MgSO4+H2
mg+H2Co3----->MgCO3 +H2.
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Answer 2

1)In test tube A=H2SO4(strong acid)
in test tube B=H2CO3( weak acid)
so,the reaction take place vigorous in strong acid.
hence, In test tube A the reaction take place vigorous .

2)The gas which is elaborate is hydrogen gas (H2).
when hydrogen gas is taken to the burning candle it produce pop sound.
By this property we can check.

3)In test tube A

H2SO4+Mg----->MgSO4+H2

in test tube B

H2CO3+Mg----->MgCO3+H2