Equal lengths of Magnesium ribbon are taken in two test tubes "A" and "B".
Sulphuric acid is taken in test tube "A" and carbonic acid is taken in "B" in equal amounts.
a) Identify the test tube that will show vigorous reaction.
b) Write a balanced equation for the reaction of the above metal with sulphuric acid and
carbonic acid.
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Answered by
3
Answer:
plzz sopport me mates
Explanation:
Fizzing in the reaction is due to evolution of hydrogen gas by the action of metal on acid.
In test tube A :
Mg(s) + 2HCl(aq) →MgCl2(aq) + H2(g)
In test tube B :
Mg + CH3COOH(aq) → (CH3COO)2Mg + H2(g)
Since hydrochloric acid is a strong acid and acetic acid is a weak acid, so evolution of H2 gas occurs more readily in case of HCl.
Answered by
0
Answer:
thamizhaa bro neenga and thanks for thanks bro
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