Equal masses of CO and CO2 are mixed in an empty
container at 400 K. And the total pressure inside the
container is found to be 10 atm. Calculate the
pressure due to CO2 (approximately) in container.
Answers
Answer:
ANSWER
Equal masses of methane and oxygen are mixed in an empty container at 25
o
C. The fraction of the total pressure exerted by oxygen is
3
1
.
Let 32 g of oxygen are mixed with 32 g of methane.
The molar masses of methane and oxygen are 16 g/mol and 32 g/mole respectively
The number of moles of methane =
16g
32g
=2moles.
The number of moles of oxygen =
32g
32g
=1mole.
Total number of moles =2+1=3.
The mole fraction of oxygen =
1+2
1
=
3
1
.
The mole fraction is proportional to the fraction of the total pressure exerted.
Hence, the fraction of the total pressure exerted by oxygen is
3
1
.
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Answer:
The fraction of the total pressure exerted by oxygen is 3.
Explanation:
As given in the question,
Equal masses of CO and CO2 are mixed in an empty container at 400 K. And the total pressure inside the container is found to be 10 atm.
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Let 32 g of oxygen are mixed with 32 g of methane.
The molar masses of methane and oxygen are 16 g/mol and 32 g/mole respectively
The number of moles of methane = 2 mole
The number of moles of oxygen = 1 mole
Total number of moles =2+1=3.
The mole fraction of oxygen = 3
The mole fraction is proportional to the fraction of the total pressure exerted.
Hence, the fraction of the total pressure exerted by oxygen is 3.
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