Equal masses of methane and oxygen are mixed in an empty container at 25oC. The fraction of the total pressuer exerted by oxygen is:
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Let 32 g of oxygen are mixed with 32 g of methane.
The molar masses of methane and oxygen are 16 g/mol and 32 g/mole respectively
The number of moles of methane = 32g/16g =2moles.
The number of moles of oxygen = 32g/32g =1mole.
Total number of moles =2+1=3.
The mole fraction of oxygen = 1/1+2 =1/3
The mole fraction is proportional to the fraction of the total pressure exerted.
Hence, the fraction of the total pressure exerted by oxygen is
1/3
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