Question

equal masses of O2 H2 and ch4 are taken in a container their respective mole ratio of these gases in container in container is​

Answer 1

Answer:

Explanation:

1) Convert the mass into moles (use the formula n=m/Mr) :

Since the masses are equal, you can take the mass as x. So, the number of moles would be:

• n(O2) = x/32
• n(H2) = x/2
• n(CH4) = x/16

2) Divide the moles by the smallest value :

Since under identical conditions, the same number of moles occupy the same volume, you can directly divide by the smallest value. Now, which one is the smallest value? Simple. The one with the largest denominator has the smallest value. For example, 1/25 is smaller than 1/10.

So, x/32 is the smallest.

(x/32)/(x/32) = 1.  

Similarly, you can do it for the others. This now gives us the ratio of:

1:16:2

O2:H2:CH4