Question

Equal masses of oxygen, hydrogen and CH4 are taken in a container. What is the respective mole ratio of these gases in the container?

Answer 1

If equal masses of substances are taken, mole ratio will be inversely proportional to molar mass.
So Mole ratio of $O_{2}:H_{2}:CH_{4}=\frac{1}{32}:\frac{1}{2}:\frac{1}{16}=1:16:2$

Answer 2

Answer: The mole ratio of the given gases in the container is 1 : 16 : 2

Explanation:

Mole ratio is defined as the ratio of number of moles of the two substances taken into account.

Let us assume that the mass of the given gases are 1 g.

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

• For oxygen gas:

Given mass of oxygen gas = 1 g

Molar mass of oxygen gas = 32 g/mol

Putting values in above equation, we get:

$\text{Moles of oxygen gas}=\frac{1g}{32g/mol}$

• For hydrogen gas:

Given mass of hydrogen gas = 1 g

Molar mass of hydrogen gas = 2 g/mol

Putting values in above equation, we get:

$\text{Moles of hydrogen gas}=\frac{1g}{2g/mol}$

• For methane gas:

Given mass of methane gas = 1 g

Molar mass of methane gas = 16 g/mol

Putting values in above equation, we get:

$\text{Moles of methane gas}=\frac{1g}{16g/mol}$

Taking the ratio of their moles, we get:

$O_2:H_2:CH_4=\frac{1}{32}:\frac{1}{2}:\frac{1}{16}\\\\O_2:H_2:CH_4=1:16:2$

Hence, the mole ratio of the given gases in the container is 1 : 16 : 2