Question

Equal masses of oxygen, hydrogen and methane are kept under identical conditions. The ratio of the volumes of gases will be

Answer 1

To make it concrete, assume you have 32 grams of each gas 32.0 g O2 x (1 mol O2 / 32.0g O2) = 1 mol 32.0 g H2 x (1 mol H2 / 2.0g H2) = 16 mol 32.0 g CH4 x (1 mol CH4 / 16.0g CH4) = 2 mol CH4 

Answer 2

Hey !!

Oxygen             Hydrogen              Methane

  (O₂)                    (H₂)                         (CH₄)

Number of moles

$\frac{1}{34} = 0.031 , \frac{1}{2} = 0.5 ; \frac{1}{16} = 0.0625$

Simple Ratio     1       6       2

Equal number of moles of gases occupy equal volumes under similar conditions of temperature and pressure, therefore the ratio of the volumes of gases will be

                         1 : 16 : 2

Good luck !!