Question

Equal masses of oxygen, hydrogen, and methane are taken in a contaainer in identical conditions. find the ratio of the volume of the gases?​

Answer 1

Answer:

1) Convert the mass into moles (use the formula [math]n = m/M_r[/math])

Since the masses are equal, you can take the mass as x. So, the number of moles would be:

[math]n(O_2)[/math] = x/32

[math]n(H_2)[/math] = x/2

[math]n(CH_4)[/math] = x/16

2) Divide the moles by the smallest value

Since under identical conditions, the same number of moles occupy the same volume, you can directly divide by the smallest value. Now, which one is the smallest value? Simple. The one with the largest denominator has the smallest value. For example, 1/25 is smaller than 1/10.

So, x/32 is the smallest.

(x/32)/(x/32) = 1.

Similarly, you can do it for the others. This now gives us the ratio of:

1:16:2

hope it helps you