Math, asked by sujith8418, 11 months ago

Equal sums of money were invested in scheme A and scheme B for two years. Scheme A offers simple interest and scheme B offers compound interest (compounded annually) and the rate of interest (p.c.p.a) for both the schemes are same. The interest accrued from Scheme A after two years is Rs. 2560/- and from scheme B is Rs. 2688/-. Had the rate of interest (p.c.p.a) of scheme A been 6% more, what would have been the interest accrued from Scheme A after two years?​

Answers

Answered by sk940178
2

Answer:

Rs. 4096/-

Step-by-step explanation:

Let us assume that the sum of money is x Rs. and the interest rate is r% for both scheme A and B.

Given that the time of investment is 2 years for both schemes.

Also given,

For scheme A the interest rate is simple and the interest accrued is 2560 Rs.

For scheme B the interest rate is compound and the interest accrued is 2688 Rs.

Now, for scheme A,

interest accrued = \frac{2x}{100} r=2560

\frac{xr}{50}=2560 ..... (1)

xr=128000 .....(2)

Now, for scheme B,

interest accrued =\frac{xr}{100}+\frac{(x+\frac{xr}{100} )}{100}r=2688

\frac{2xr}{100}+\frac{xr^{2} }{10000}=2688

\frac{xr}{50}+\frac{xr}{10000}r=2688

⇒2560+\frac{128000}{10000}r=2688 {Using equation (1)}

⇒12.8r=128

⇒ r=10

So, the interest rate is 10%.

Now, from equation (2), x=\frac{128000}{r}=12800.

So, the invested sum is 12800 Rs.

If the interest rate is increased by 6% for the scheme A, i.e. (10+6)%=16%, then the interest accrued would have been after 2 years

=\frac{2xR}{100} {Where, R=16% i.e. the new interest rate}

=\frac{2*12800*16}{100}

=4096 Rs. (Answer)

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