Question

Equal volume of 0.1m hcl and 0.1m naoh are mixed the concentration of resulting solution

Answer 1

Let volume of each solution is V.

given, concentration of HCl = 0.1M

so, normality of HCl = n- factor × molarity of HCl = 1 × 0.1V = 0.1 N

similarly, concentration of NaOH = 0.1M

so, normality of NaOH = 1 × 0.1M [ n-factor of NaOH = 1] = 0.1N

then after mixing,

$N_1V_1+N_2V_2=N_f(V_1+V_2)$

or, 0.1N × V + 0.1N × V = $N_f$ × (V + V)

or, 0.2NV = $N_f$ (2V)

or, $N_f$ = 0.1N

hence, normality of mixture is 0.1N

we know, NaOH + HCl => NaCl + H2O

so, n-factor of NaCl = +1

so, molarity/concentration of NaCl = 0.1/1 = 0.1M