equal volume of 0.2 molar NH4OH and 0.1 molar of H2SO4 are mixed calculate pH of final solution Kb of nh4oh h is 2 ×10^-5 .
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NH4OH + (NH4)2SO4 ——→ 3NH3 + SO3 + 2H2O
As the resulting mixture has ammonia and sulphur trioxide . Both are fairly weak basses so the resulting solution will have a pH value greater than 7. But if water reacts with SO3 then the solution will turn towards acidic character due to the formation of sulphioric acid :-)
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As the resulting mixture has ammonia and sulphur trioxide . Both are fairly weak basses so the resulting solution will have a pH value greater than 7. But if water reacts with SO3 then the solution will turn towards acidic character due to the formation of sulphioric acid :-)
hope it helps
plz mark it as brainlist
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Answer:
NH4OH + (NH4)2SO4 ——→ 3NH3 + SO3 + 2H2O
As the resulting mixture has ammonia and sulphur trioxide . Both are fairly weak basses so the resulting solution will have a pH value greater than 7. But if water reacts with SO3 then the solution will turn towards acidic character due to the formation of sulphioric acid
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