Question

Equal volume of 5.85%(w/v) Nacl and 17.55%(w/v) Nacl solutions are mixed if volume of mixture is 2.5L then find number of moles of na+ present in mixture

Answer 1

Let us mix 100 ml + 100ml = 200 ml

200 ml will contain 5.85+17.55 = 23.4 g = 11.7% w/v

therefore 1 L will contain 117 g

and 2.5 litres will contain 117 x 2.5 = 292.5 g = 292.5/58.5 moles

= 5 moles.

5 moles of NaCl will the present in the mixture of 2.5 L