equal volume of each 10% HCL and 10% and naoh
is mixed comment on the nature of resulting solution
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The concentrations are effectively 0 provided you had molecule for molecule parity in reagents, and ignoring the autolytic reaction of water. All of the OH- is going to pick up all the acidic H+ on those hydroniums.
You didn't ask about the leftover Na+ and Cl- ions.
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