Equal volume of oxygen and second gas weight one and 1.375 gram and the same experimental conditions which is the unknown gas
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Explanation:
Since, the gases occupy same volumes at same experimental conditions, this means that
Moles of Oxygen present in 1.0 gm of Oxygen gas = Moles of Gas present 1.375 gm of that gas
Let the molecular mass of the unkonwn gas be M gm/mol
O2
1
M=1.375
M=76 gm/mol
Of the above gases, CS2
has a molecular mass of 76 gm/mol.
I think you did not provide the options. since I was asked the same question earlier...the answer is CS2
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