Question

Equal volume ofN2 and H2 react to form ammonia under suitable condition then the limiting reagent is

Answer 1

Answer:

When equal volume of  react, the limiting reagent is .

Explanation:

A limiting reagent or a limiting reactant is that substance in a chemical reaction that gets completely consumed when a reaction is complete. It is important to identify a limiting reagent in a chemical reaction so that the amount of the product obtained can be calculated.

When equal quantities of  react, we get the balanced equation as given below:

According to mole ratio, 1 mole of  needs 3 moles of  to form 2 moles of ammonia.

We are given that  and  are in equal quantities and so for every  only 1 mole of  is provided whereas 3 moles of H_2 are required to fully react.

This means that there is not enough  to react with the given quantity of  and so  is limiting reagent.

Explanation:

Answer 2

Let the volume of $N_2=H_2=3L$

Balanced chemical equation

$N_2+3H_2 \rightarrow 2NH_3$

According to the balanced equation

$1V$ of $N_2$ reacts with 3V of $H_2$ to produce 2V of $NH_3$

1V of $N_2$ requires 3V of $H_2$

3V of $N_2$ will require 9V of $H_2$

But we have only 3V of $H_2$

Hence $H_2$ is L.R

Now,

3V of $H_2$ will react with 1V of $N_2$

Unreached $N_2 =3-1=2V$

#SPJ3