Question

Equal volumes of 0.200 M HCl and 0.600
M NaOH are mixed. The concentrations of
the principal ions in the resulting solution are
(1) [Na+] =0.400 M [CI- ]= 0.200 M [H+ ]= 0.200 M
(2)[Na+]= 0.300 M [CI -]=0.100 M [OH-]=0.200M
(3) [Na+]= 0.100 M [Cl-]= 0.100 M [OH-]= 0.100 M
(4)[Na+] 0.200 M [Cl-]=0.100M [H+]=0.100M

Answer 1

Answer:

option 2

Explanation:

Only 0.2 moles NaOH will be used for the reaction.

The remaining 0.400 moles of NaOH is responsible for the conc of OH - ions = 0.400/2 = 0.200 M.

The remaining conc of Na+ ions will be equal to 0.200/2 (from NaCl) and 0.400/2 (from dissociation of NaOH) = 0.300.

Therefore

[Na+] = 0.300 M

[Cl-] = 0.100 M

[OH-] = 0.200 M