Question

Equal volumes of methane and ethane are mixed in an empty container at 25C. The fraction of total pressure exerted by ethane is?

A. 1/2

B. 2/3

C. 8/15

D. 3/2

Answer 1

P1V1=n1R1T1
P2V2=n2R2T2
R,T,=const
(P1V1)n1 = (P2V2)/n2

n1=n2 
when volumes are equal

P1V1=P2V2, when 
V1=XV2
P1XV2=P2V2
xP1=P2

ratio of the pressures is inversely 
proportional

Answer 2

Answer:

Their answer would be D. 3/2

Explanation:

Molar mass => C2H6 = 30

Molar mass => CH4 = 16

Equal weight of both C2H6 and CH4 = 30

N-c2H6 = 30/30 = 1

N-cH4 = 30/16

Fraction of total pressure exerted by methane = 30/16 / 30/16 + 1 = X(B)

= 30/16/30+16/16 = 30/46 = 15/23

And at 15/23, it is further canceled out then it would result as 3/2

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