Equal volumes of oxygen gas and a second gas weight 1.00 and 2.375 grams respectively under the same experimental conditions. wch of the following is the unknown gas?
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Molar mass of unknown gas is 76
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v1=v2 given as we know that pv=nRT therefore v is directly propotional to n so n1=n2
n1=1/32 (O2) n2= 2.375/n2 therefore molar mass of is 76 and 76 is cs2 that is c option
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