Equal volumes of oxygen gas and second gas weigh 1 and19/8 gm resp find gas
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Since, the gases occupy same volumes at same experimental conditions, this means that
Moles of Oxygen present in 1.0 gm of Oxygen gas = Moles of Gas present 2.375 gm of that gas
Let the molecular mass of the unkonwn gas be M gm/mol
⟹ 1/32
= 2.375/M
⟹M=76 gm/mol
Of the above gases, CS sq
has a molecular mass of 76 gm/mol.
Explanation:
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