Equal volumes of two solution one having ph equal to 6 and other having ph equal to 4 are mixed the ph of the resulting solution will be
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let v be the volume of the solution.the solutions are of concentrations of 10^(-6)M and 10^(-4) M respectively.now 10^(-6)v+10^(-4) v =( 2v)×y, where y is molarity of the new solution.take negative logarithm of this "y", and u will get pH of the resulting solution.
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