Equal volumes of two solutions of NaOH, one having
pH = 10 and other having pH = 12 are mixed together.
The pOH value for the resultant solution is
Answers
Answered by
0
Answer:
12.because here 12 dominates
Answered by
0
Answer:
4.3
Explanation:
pH=4, pH=6
For pH=4, [H+]=10−4M
For pH=6, [H+]=10−6M
Molarity=volumeno. of moles
Let the volume be V.
No. of moles, n1=10−4×V
No. of moles, n2=10−6×V
Net number of moles after mixing = 10−4×V+10−6×V
Net [H+] concentration = 2V10−4×V+10−6×V
pH = −log[H+]
pH = 4.3
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