Question

Equal weight of He and CH4 are present in a container then find the % weight of He.

Answer 1

Answer:

50%

Explanation:

because two are of equal weight

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Answer 2

Atomic Wt. (He) = 4 g

Atomic Wt. ( CH4 ) = 12 + 4 x 1 = 12 + 4 = 16 g

Total Wt. = 4 +16 g = 20 g

Percentage Wt. of He = (4/20) * 100

= 1/5 * 100 = 20 %

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